15b^2-17bc-4c^2=0

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Solution for 15b^2-17bc-4c^2=0 equation: 


Simplifying
15b2 + -17bc + -4c2 = 0

Reorder the terms:
-17bc + 15b2 + -4c2 = 0

Solving
-17bc + 15b2 + -4c2 = 0

Solving for variable 'b'.

Factor a trinomial.
(3b + -4c)(5b + c) = 0


Subproblem 1
Set the factor '(3b + -4c)' equal to zero and attempt to solve:

Simplifying
3b + -4c = 0

Solving
3b + -4c = 0

Move all terms containing b to the left, all other terms to the right.

Add '4c' to each side of the equation.
3b + -4c + 4c = 0 + 4c

Combine like terms: -4c + 4c = 0
3b + 0 = 0 + 4c
3b = 0 + 4c
Remove the zero:
3b = 4c

Divide each side by '3'.
b = 1.333333333c

Simplifying
b = 1.333333333c

Subproblem 2
Set the factor '(5b + c)' equal to zero and attempt to solve:

Simplifying
5b + c = 0

Solving
5b + c = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1c' to each side of the equation.
5b + c + -1c = 0 + -1c

Combine like terms: c + -1c = 0
5b + 0 = 0 + -1c
5b = 0 + -1c
Remove the zero:
5b = -1c

Divide each side by '5'.
b = -0.2c

Simplifying
b = -0.2c
Solution
b = {1.333333333c, -0.2c}

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